A Poster Can Have A Maximum Perimeter Of 42 Inches Long

May 20, 2024

So let's think about. And, ∴ Overall dimensions of the page in order to maximize the printing area is page should be 11 inches wide and 10 inches long. For example, what I learned was 78/2 and then take that answer and subtract by the one length that the problem gives you, because the formula that I learned was 2(L+W). Ask a live tutor for help now. The area of a square is 144 square centimeters. A poster can have a maximum perimeter of 42 inchem.org. If we added this distance, 21 feet, to this distance, the width, plus 21 feet to the width again, we're going to get to 78 feet. So what are two distances, or what are two numbers that I can add together to get to 36?

  1. A poster can have a maximum perimeter of 42 inches in cm
  2. A poster can have a maximum perimeter of 42 inches high
  3. A poster can have a maximum perimeter of 42 inchem.org

A Poster Can Have A Maximum Perimeter Of 42 Inches In Cm

Let's find: =, for area to be maximum = 0. Check the full answer on App Gauthmath. Let's assume width of the page be x inches and its length be y inches So, Perimeter = 42 inches. And what's that going to be equal to? 5 inches from each side. A poster can have a maximum perimeter of 42 inches to feet. So let's draw what it might look like. And we know how we figure out the perimeter. Created by Sal Khan. Sal figures out the width of a dog pen. So we need to figure out the width. This positive number is 12.

A Poster Can Have A Maximum Perimeter Of 42 Inches High

What is the length of one side of the square? Depth is not something that you would calculate so much as you would just measure it. The formula is pi times the radius squared. A page should have perimeter of 42 inches. The printing area within the page would be determined by - Brainly.com. Next, you subtract 8 from the perimeter which is 26, and the difference is 18. And of course, if that distance is 21 feet, this distance is also going to be 21 feet. Which is, of course, equal to-- 36 plus 42 is equal to 78, which is the perimeter. Unlimited access to all gallery answers. Gauth Tutor Solution. And 78 minus 42-- I don't want to make a careless mistake-- 78 minus 42 is going to get me to 36.

A Poster Can Have A Maximum Perimeter Of 42 Inchem.Org

And the width would be this length-- or this width, I should say-- this width, which is going to be the same thing as that width right over here. So we need to find what positive number times itself would give 144. And you add the two lengths, plus 21 plus 21. So one way to back into what the width is is to say, well, look if we sum up all of these lengths, we're going to get 28 feet. Its length is 21 feet. So it might look something like this. A poster can have a maximum perimeter of 42 inches 6 pockets. And we can verify that. What is the width of Mike's dog pen? Let's do 78 minus 21 minus 21. Im bored, school is boring(7 votes). Crop a question and search for answer. And then we figure out how much length essentially these two widths have to make up. This is what we needed the two widths to add up to-- plus 42. So that's 78 minus 42.

These are the exact same width, that this distance is the same as this distance. Width of printed area = x-3 & length of printed area = y-2: area =. And let's remind ourselves what 36 feet is. And they give us its length. So the perimeter is 78 feet.